Apply the translation theorem to find the inverse Laplace transform of the following function. 5 F(S) = 2s - 14 Click the icon to view the table of Laplace transforms. Reference f (t ) = e-(F(s)} L(f(t)} = F(s) f(t) = e-1{F(s)} 2{f(t)} = F(s) 2- 1 { F ( S)) = S (s > 0) (Type an expression using t as the variable.) cos kt - o 1 - SZ + 1 2 (s > 0) k + 2 (s > 0) sin kt S s + K 2 (s > 0) n! S n+ 1 (s > 0) cosh kt S (s > |kl) T(a + 1) ta k h+1 (s > 0) sinh kt $2 -12 (s > | KI) 1 e at n! (s > a) e atn s- a (s- a)+1 (s> a)