Approximate the area under The graph of x] = [[0314 2.25)(2 + 85 over the interval [5,9] by dividing the interval into 4 subintervals. Use the left endpoint of each sublnterval. The area under the graph of fix} = 0.03314 2_25x2 +85 over the interval [5,9] is approximately D. [Simplify your answer. Type an integer or a decimal]