Armer Company is accumulating data to use in preparing its annual profit plan for the coming year. The cost behavior pattern of the maintenance costs must be determined. The accounting staff has suggested the use of linear regression to derive an equation for maintenance hours and costs. Data regarding the maintenance hours and costs for the last year and the results of the regression analysis follow: 2 Maintenance Machine Month Cost 4,750 3,550 4,150 3,370 4,900 3,510 3,580 5,020 4,810 4,600 3,850 3,710 Hours Jan. Feb. Mar. Apr. May June July Aug. Sept. oct. Nov. Dec. Sum Average 700 540 620 520 720 530 540 780 710 690 570 560 7,480 623 $49,800 8 4.150 May June July Aug. Sept. oct. Nov. Dec. Sum Average Average cost per hour a (intercept) b (coefficient) Standard error of the estimate R-squared t-value for b 4,900 3,510 3,580 5,020 4,810 4,600 3,850 3,710 $49,800 720 530 540 780 710 690 570 560 7,480 4,150 623 $ 7.00 $81.9267 6.7892 83.4170 ol 9838 39.130 The percent of the total variance that can be explained by the regression equation is 349.378%. None of these answer choices are correct 98.383%. 195.946%. 745.604%