As an investigation of energy and work, you will return to the modified Atwood's machine. The standard Atwood's machine has two masses attached to each other by a string which is threaded over a pulley. In this case, the heavier mass is placed in the water, allowing the heavier weight to rise. In the previous investigation, you investigated the acceleration at different points as the larger block rose. In this one, you will investigate how to account for the energy of the buoyant force in an energy diagram and how to interpret it. O In this Atwood's machine, the heavier weight is a cube (1) with a side length of 5.83 cm and a mass of 248 9. The lighter cube (2) has a side length of 5.3 cm and a mass of 186 9. In the initial configuration, the large block rests on the bottom of a water column 13 cm deep, and attached to the other side of the string, the small block is 37 cm above the ground. Measure heights as distances of the bottoms of the cubes from the bottom of the cylinder. As it rises, it undergoes three different processes, processes that require different physics to solve. The first process is rising while submerged in the water, the second process is emerging from the water, and the final process is rising while in the air. (B) (C III (B) (D) Part 3 of 8 - Position A: Initial Configuration The changes between the phases occur when the top of the block touches the water at D-s, and when it finally emerges when it's bottom is at the water level D. Start with the initial energy. In order to determine the initial energy of the system, you need to account for the speeds and positions of the two blocks. Because they are connected by the string, the two blocks have the same speed, and so the kinetic energy can be easily combined, but it would be best to handle the two potential energies individually. To find the energies, you'll need to know the positions and velocities of the two blocks. (a) Find the position of the larger block. HA = 7.17 cm x 2 (b) Find the velocity of the larger block. VA = (c) Find the position of the smaller block. hA = (d) Find the velocity of the smaller block. VA = (A) Now you can find the energies. (f) Write out the energy equation for the initial configuration (A). EA =