As in the previous problem, 84 students are randomly selected from an accounting class at a local college. If X is the number of students who received a B or above on the final exam, then the distribution of X can be approximated with a normal distribution, N(42,4.6), where the mean () is 42 and standard deviation () is 4.6. Using this approximation, find the probability of 45 or 46 students receiving a B or above on the final exam in an accounting class. You may use the portion of the Standard Normal Table below. z0.50.60.70.80.91.01.10.000.69150.72570.75800.78810.81590.84130.86430.010.69500.72910.76110.79100.81860.84380.86650.020.69850.73240.76420.79390.82120.84610.86860.030.70190.73570.76730.79670.82380.84850.87080.040.70540.73890.77040.79950.82640.85080.87290.050.70880.74220.77340.80230.82890.85310.87490.060.71230.74540.77640.80510.83150.85540.87700.070.71570.74860.77940.80780.83400.85770.87900.080.71900.75170.78230.81060.83650.85990.88100.090.72240.75490.78520.81330.83890.86210.8830 Round the final answer to two decimal places