As in the univariate case, a Taylor polynomial of a function does not contain enough data about the original function to recover it exactly. However, if we have enough information about the original function, we may be able to make deductions using this data. Note: Remember to write your answers using Matlab syntax. For example, ce + - 2x + 3 would be written as (y - 1)2 x*2*exp (2) + (2*x+3) / (y-1) ^2 For example, suppose we know that the function f : R -> R has the form f(x, y)= by + c (i) Suppose we also know the first-order Taylor polynomial of f at (0, 1) (in expanded form) is 9 3x PI(x, y) = 2y 49 + 7 49 Then we may deduce that the exact values of a, b and c are b C=(ii) Now that we have deduced the coefficients in our original function, we can find the second-order Taylor polynomial p2 (@, y). In particular, we find that the quadratic terms in x and y - 1 (that is, those terms of the form a (y - 1) and (y - 1)2) are given by the difference of Taylor polynomials, P2(x, y) - P1(x, y) =