As shown below, a charged particle is moving through a region that has a uniform 1,400 N/C E-field (the red lines) and a uniform 8.8 T B-field. As a result of these two fields and the resulting forces (ignore gravity), the particle has a constant velocity. A.) Determine the directions of FE & FB on the particle. Direction of FE = Direction of FB B.) Determine the particle's speed and the direction of the B-field. Assume that the B-field is perpendicular to the velocity. v = Direction of B