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Consider the same assumption in previous question. In addition, we consider a possible vomiting out of coughing as shown in the following network, where V= vomiting (v or v). We assume that P(vc)=0.1 and P(vc)=0.2. Use Bayesian exact inference to obtain the following probabilities: 1. P(f,a,c,v) 2. P(fv) 3. P(af,v) 4. P(fa,c,v)