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Assignment 1 course name fundamentals of routing and switching he Internet can contain viruses. Unless you need to edit, it's safer to stay in Protected

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Assignment 1 course name fundamentals of routing and switching

he Internet can contain viruses. Unless you need to edit, it's safer to stay in Protected View. Enable Editing Following example is true for problem 1-3. Given Number of needed subnets: 4 Network Address: 192.168.10.0/24 or 192.168.10.0 255.255.255.0 We are given a network for example: 192.168.10.0/24 or 192.168.10.0 255.255.255.0. This means that/24 = 255.255.255.0 So here 192.168.10.0 is the network that I have right now at my disposal. This network has 256 IP addresses or hosts. What I need to do is to subdivide this ONE network into FOUR equal size networks (because number of subnets here that are needed are 4). This means that each network should have 256/4 = 64 IP addresses per subnet. Address Class = C Default Subnet Mask = /24 or 255.255.255.0 Customer Subnet Mask = /26 or 255.255.255.192. Total number of subnets = 4 Total number of IP addresses per subnet = 64 Total number of usable IP addresses per subnet = 62 Number of bits borrowed = 2 Problem 1: Given Number of needed subnets: Network Address: 6 195.10.0.0/24 Find Address class Default subnet mask Custom stihnet mask Focus -4C 2 hings Review View Help Enable Editing om the Internet can contain viruses. Unless you need to edit, it's safer to stay in Protected View. Total number of IP addresses per subnet = 64 Total number of usable IP addresses per subnet = 62 Number of bits borrowed = 2 Problem 1: Given Number of needed subnets: Network Address: 6 195.10.0.0/24 Find Address class Default subnet mask Custom subnet mask Total number of subnets Total number of IP addresses/per subnet Number of usable addresses/per subnet Number of bits borrowed Problem 2: Given Number of needed usable hosts: Network Address: 126 200.0.0.0/24 Find Address class Default subnet mask Assignment1 (1) - Protected View Saved to this PC O Search (Alt+Q) Design Layout A Nikha References Mailings Review View Help n the Internet can contain viruses. Unless you need to edit, it's safer to stay in Protected View. Enable Editing Problem 2: Given Number of needed usable hosts: Network Address: 126 200.0.0.0/24 Find Address class Default subnet mask Custom subnet mask Total number of subnets Total number of IP addresses/per subnet Number of usable addresses/per subnet Number of bits borrowed Assignment (1) - Protected ViewSaved to this PC o search Catrol Nikhalpro sign Layout References Mailings Review View Help the Internet can contain viruses. Unless you need to edit, it's safer to stay in Protected View. Enable Editing Problem 3: Given Number of needed usable hosts: Network Address: 15 198.100.0.0/24 Find Address class Default subnet mask Custom subnet mask Total number of subnets Total number of IP addresses/per subnet Number of usable addresses/per subnet Number of bits borrowed Nikhalpreet Kaur Design Layout References Mailings Review View Help s from the Internet can contain viruses. Unless you need to edit, it's safer to stay in Protected View. Enable Editing Problem 4: In the network below the router, R_OAK, has three interfaces connected to three LANS. Given a class C address block of 198.1.30.0, create an addressing scheme that will allow each network segment to have 62 hosts. Update (annotate) the diagram with IP addresses for each router interface, and subnet addresses for each LAN. Network: 198.1..30.0/24 LAN1 ROAK LAN3 SW1 SW3 LAN2 SW2 I Total number of collision domains: Total number of broadcast domains: Focus arch W -4C from the Internet can contain viruses. Unless you need to edit, it's safer to stay in Protected View. Enable Editing Total number of collision domains: Total number of broadcast domains: New Subnet Mask for each LAN: CIDR Notation: Subnetting Scheme: Subnet # Subnet Address 0 Broadcast address IP Address Range 1 2 3 4 5 6 7 I em the Internet can contain viruses. Unless you need to edit, it's safer to stay in Protected View. Enable Editing 0 1 2 3 4 5 6. 7 Valid host address range Default GW Subnet Allocation in LANS LAN Subnet address LAN1 LAN2 LAN3 Focus Problem 5: In the network below the routers, R_OAK and R_BRA connect 4 LANs in two sites. Given a class C address block of 215.1.1.0/24, create an addressing scheme that will allow LAN1 to have 30 hosts, LAN 2 to have 50 hosts, LAN 3 to have 25 hosts and LAN 4 to have 10 hosts. Network: 215.1.1.0/24 ROAK R_BRA SW1 SW3 LAN1 LAN3 I SW2 SW4 LAN4 LAN2 D. Focus O JUL -4C Enable Editing es from the Internet can contain viruses. Unless you need to edit, it's safer to stay in Protected View. TANA LAN2 YOU NEED TO ENSURE THAT YOU ARE NOT WASTING IP ADDRESSES. YOUR ANSWER WILL BE CONSIDERED WRONG IF YOU ANSWER THE QUESTION BUT WASTED IP ADDRESSES. YOU NEED TO ALSO SHOW SUBNETS THAT ARE STILL AVAILABLE AFTER YOUR SUBNET ALLOCATION FOR LAN1, LAN2, LAN3 & LAN4. Answer the following questions for each LAN: Valid host address range Default GW Subnet Allocation in LANS LAN Subnet address LAN1 LAN2 LAN3 LAN4

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