Assignment $1-$ Truss Element

Find the horizontal displacement of node $1.$

$m^2$

${10}^6\frac{N}{m^2}$

Consider node $1$ as the origin $(0,0).$

To find the angle of each element, you must use this formula :

$=ta{n}^{-1}(\frac{Y_j-Y_i}{x_j-x_i})$

$x_j$ and $Y_j$ is the coordinate for the $2^{nd}$ node of each element $x_i$ and $Y_i$ is the coordinate for the $1^{st}$ node of each element