Assignment #4 - Describing Data - Chapter 9 - Summer 2022 For the table below, fill in the missing sections for the Mean, Median, Mode, Range, and Standard Deviation on your own. For this task, round to two decimal places. Hint: Put the data into SPSS to simplify the calculation of the standard deviation! Use the "Means" test under Analyze. Include the correct "options". Then complete the five questions and transfer your answers to the quiz in Canvas. (One point per question) Condition 1 Scores Condition 2 Scores 5 6 7 5 7 6 N a w Column Mean Column Median Column Mode Standard Deviation Column Range 1. The correct mean for Condition One is while the correct mean for Condition Two is A. 4.87 and 6.20 B. 6.00 and 5.00 C. 6.07 and 5.33 D. 6.20 and 4.87 E. 7.00 and 4.002. The correct standard deviation for Condition One is while the correct standard deviation for Condition Two is A. 1.30 and 1.97 B. 1.30 and 4.87 C. 1.97 and 1.97 D. 1.97 and 1.30 E. 6.20 and 4.87 3. Which of the following is true about the mode? A. Conditions One has one mode and Condition Two has one mode B. Condition One has one mode while Condition Two has two modes C. Condition One has two modes while Condition Two has one mode D. Condition One has two modes and Condition Two has two modes 3. Imagine you ran a f-Test on this data to see if Condition One differs significantly from Condition Two. You got the following Independent Samples Test table: Independent Samples Test Levene's Test for Equality of Variances t-test for Equality of Means F Sig. df Sig. (2-tailed) Score Equal variances 1.872 182 2.186 28 037 assumed Equal variances 2.186 24.262 .039 not assumed 4. What is the best interpretation for this t-Test? A. It was significant, /(28) = 2.19, p = .039 B. It was significant, (28) = 2.19, p = .037 C. It was not significant, /(28) = 1.87 p= .182 D. It was not significant, ((28) = 1.87, p = .039 E. It was not significant, (24.26) = 2.19, p= .395. Use the Independent Samples Test table as well as your findings for the mean and SDs (from questions #1 and #2) and the /-Test write up from question #3 to determine which of the following f-Test write-ups is correct: A. We ran an independent samples -Test with score as the dependent variable and condition (1 versus 2) as the independent variable, which was significant, ((28) = 2.19, p = .037. Scores were significantly higher in condition 1 (M = 6.20, SD = 1.97) than in condition 2 (M = 4.87, SD = 1.30). B. We ran an independent samples f-Test with score as the dependent variable and condition (1 versus 2) as the independent variable, which was significant, (28) = 2.19, p = .037. Scores were significantly higher in condition 1 (M = 4.87, SD = 1.30) than in condition 2 (M = 6.20, SD = 1.97). C. We ran an independent samples t-Test with score as the dependent variable and condition (1 versus 2) as the independent variable, which was significant, (28) = 1.87, p = .039. Scores were significantly higher in condition 1 (M = 6.20, SD = 1.97) than in condition 2 (M = 4.87, SD = 1.30). D. We ran an independent samples t-Test with score as the dependent variable and condition (1 versus 2) as the independent variable, which was not significant, ((28) = 1.87, p =.182. Scores did not differ significantly between condition 1 (M = 6.20, SD = 1.97) and condition 2 (M = 4.87, SD = 1.30). E. We ran an independent samples t-Test with score as the dependent variable and condition (1 versus 2) as the independent variable, which was not significant, (28) = 2.19, p =.037. Scores did not differ significantly between condition 1 (M = 6.20, SD = 1.97) and condition 2 (M = 4.87, SD = 1.30)