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Assume I conducted an experiment similar to the lab activity you performed last fortnight. I measured the time it took for the capacitor to discharge

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Assume I conducted an experiment similar to the lab activity you performed last fortnight. I measured the time it took for the capacitor to discharge to 50% of its initial value 5 times. I calculated the average of the time measurements to be 5.5368 s, and the standard deviation of the time measurements to be 0.287 41 s. What is the uncertainty in my time measurement? O 0.575 s O 0.57 s O 0.6s O 0.287 s O 0.29 s O 0.3s O 0.129 s O 0.13s 0 0.1s O None of the above.This question is about the same scenario as the previous question. How would I correctly report the nominal time for my measurement? O 6.0s O 5.5s O 5.54 s O 5.537 s O 5.5368 s O 5.5368 s O None of the above.Assume I conducted an experiment similar to the lab activity you performed last fortnight, I measured the time it took for the capacitor to discharge to 10% of its initial value to be [155 :: [113) s. The simulation reported that my capitance was 1.33 pI-I Neglecting the uncertainty in the capacitance, compute the resistance of my light bulb (rounded correctly). O 21711011000001111119 O 131110011000000.111! O 1312911810032 3186!! O 2171 172 1119516125930. 0 None of the above. This question is about the same scenario as the previous question. What is the uncertainty in the light bulb resistance? 0 -10 000 000 000.0 Q Q 80 000 000 000.0 1'! O 8-105090019110138? O [2028 108' 218.702 153! 0 None of the above

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