Assume that f(t) is continuous on R. Assume also that g(x) and h(x) are differentiable on R. Let ~g(a) H (ac) = f(t) dt. Jh(xc) a) Then H(x) = Sh(x) f(t) dt + Sy() f(t) dt. b) Then H(x) = S() f(t) dt - fm(?) f(t) dt. c) Then H(x) is differentiable and the FTC and the Chain Rule tells us that H'(x) = f(g(x) )g'(x) - f(h(x) )h'(x). d) None of the above