Assume that the traffic to the web site of Smiley's People, Inc., which sells customized T-shirts, follows
Question:
Assume that the traffic to the web site of Smiley's People, Inc., which sells customized T-shirts, follows a normal distribution, with a mean of 4.42 million visitors per day and a standard deviation of 860,000 visitors per day.
What is the probability that the web site has between 3 million and 4 million visitors in a single day? If needed, round your answer to four decimal digits. Is the below, correct? There is the answer to this question, but it doesn't match mine (0.2626 is the answer) I need to know where I went wrong.
Mean = 4.42
STD DEv = 0.86
Y1 = 3
y2= 4
Need to find out probability in between two variables s;
On the left of 3:
P(x less than or equal to 3) = NORM.DIST(3, 4.42, 0.86, 1,) = 0.049352669
On the right of 4 . It's the right side so we need to find a compliment to P of less or equal to 4:
P(x is less or equal to 4) = NORM.DIST(4,4.42,0.86,1)=0.312643153
Now, the compliment as we need the right side is 1-0.312643153 = 0.687357
So the in between: 1 - 049352669 - 0.687357 = 0.26329 =0.2633