Assume that / (x) is everywhere continuous and it is given to you that f(x) + 3 lim = -3 x-+5 x - 5 that J/= 10x - 59 is the equation of the tangent line to y = f(x) at the point ( 5(1 point) The tangent line to the graph of y = f(x) at the point (2, 1) has the equation y = 3x - 5. (a) Find f'(2). f' (2) = 1 (b) Find the instantaneous rate of change of y with respect to x at x = 2. Instantaneous Rate of Change = 1(1 point) For f(x) = v3x + 22, find f '(x) using the definition f '(x) = lim (X+A)-J(X) h f ' (x) = Using this, find the tangent line to the graph of y = v3x + 22 at x = 1. Enter all values as integers, or fractions in lowest terms.(1 point) Given that f(-9) = -9 and f'(-9) = -7 , find an equation for the tangent line to the graph of y = f(x) at x = -9. -7x - 54