Assume that y is the solution of the initialvalue problem 4sinz y'+2y:{ 0 0 , 0:1. 4 95:0 y() If y is written as a
Assume that y is the solution of the initialvalue problem 4sinz y'+2y:{ \"0 \"0 , 0:1. 4 95:0 y() If y is written as a power series 00 n y = E any: n:0 then the first few terms are DDMDHUzMDm\" Note: You do not have to find a general expression for on. Just find the coefficients one by one
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