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Assume that you are writing a console-based Java application that uses the type of shape (assume rectangle, square, or circle) and computes the area and

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Assume that you are writing a console-based Java application that uses the type of shape (assume rectangle, square, or circle) and computes the area and perimeter (circumference) of that shape. The Java class Math has constant Pi (Math.PI). Show the UML diagram for class Shape including appropriate (only) getter and setter methods, and write the Java code for class Shape that has instance variables as follows String variable shapeType (rectangle, square, circle), and double length, width, and radius for the measurements. For the square only length is used Output instance variables including double area and perimeter. For the rectangle area length *width, and perimeter 2 * (length width); For the square area length*length, and perimeter 4*length; For the circle area -pi radius 2, and perimeter 2 pi * radius. Method computeShape0 in class Shape performs the computations using the input instance variables and setting the output instance variables (area and perimeter). The method does not return a value Class Shape does not perform any input or output. All input and output is in class ShapeDriver that has method main)-you need to write this method as well. In addition to processing individual shape entries you need to accumulate them in an array of type Shape. At the beginning of the main) method prompt the user for the maximum number of shapes to process. After processing the individual shapes, accumulating them in the array of type shape, output all array elements in tabular format with proper heading. You need to account for the possibility of the user entering a bad shape type or continuing beyond the maximum number of shapes. Sample input and output: OS401 Assignment number 5 - Shape Area-Perimeter calculator Enter maximum number of shapes: Enter type of shape (S for square, R for rectangle, and C for circle: Enter length/width of square: 1e Shape type s, length 10.8, width e.8, radius e.e, the area is 100.6 , and the perimeter is 40.e Do you wish to continue (y)? Enter type of shape (S for square, R for rectangle, and C for circle: Enter length of rectangle: 18 Enter width of rectangle: 20 Shape type r, length 10.8, width 20.6, radius 8.0, the area is 260.8 , and the perimeter is 68.8 Do you wish to continue (y)? Enter type of shape (S for square, R for rectangle, and C for circle: Bad shape type: x Enter type of shape (S for square, R for rectangle, and C for circle: Enter radius of circle: 10 Shape type c, length .0, width 0.0, radius 10.8, the area is 314.1592653589793 , and the perimeter is 62.83185307179586 Do you wish to continue (y)? Number of shapes processed is 3 number shape length width radius area perimeter 16.0 0.e. 100. 40.0 16.0 20.0 e. 200. 60.0 0.0 .8 18.0 314.1592653589793 62.83185307179586 End Shape Area-Perimeter calculator

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