Assume the following relations: Customer (* Cust ID, LName, FName, Address, CardType, CreditCardNo, Expiration Date, Security Code) Cust_ID LName FName Address Card Type Credit Card No Expiration Date 1000 1001 1002 1003 Thomas Trump Smith Flint Abayomi Alejandro Susan Stone Address 1 1 Address 3 Address 4 Address 2 DSIC AMEX VISA AMEX 6000 7465 9985 8334 7382 8324 9937 8438 7488 4738 2323 4323 Jan, 2019 Nov, 2020 July, 2021 April, 2022 Security Code 873 210 347 773 Product(*Prod ID, Prod_Name, Current_Price) Prod_ID PRD_75 PRD 12 PRD_14 PRD_09 Prod Name Hair Gel Shampoo Notebook Olive Oil Current Price 7.25 4.99 52.95 11.49 Purchases (*Date, * Cust ID, *Prod ID, Price) Date Cust_ID 7/11/2010 1003 2/19/2015 1003 4/04/2004 1001 5/09/2016 1003 3/05/2015 1001 Prod_ID PRD_09 PRD_09 PRD_12 PRD_09 PRD_75 Price 8.99 9.45 2.99 10.99 7.45 Using only the relational algebra operators (Select, Project, Cartesian Product, Union, Intersect) answer the following query. Query 3) Show all the purchases made by (any and all) customers with the last name Flint Stone. Show the date of purchase, Customer id, last name, first name, product id, product name, price at the time of purchase. 1) Cartesian product the Customer, Purchases, and Products relations. Put the result in a temporary table called Result_1 Result_1 = 2) extract the appropriate fields from Result_1, where the customer_id in customer relation is the same as customer_id in the purchases relation and product_id from the product relation is the same as product id in the purchases relation. Put the results in a temporary relation called Result 2; Result_2 =