Similarly for the following integrals a) I = 2x2+3x-1 dx x3+7x2 +14x+8 To factor the denominator, we more challenging x+3x+8 x3+7x2+7x-15 polynomial division well B the results: polynomial then: a) If P(x) is a (x-a) \ P(x) = P(a) = 0 8) If P(x) = x + an-1x4-1 t... faix tao then (P(p)=0 ApeQ) plaa. c) I= I { 2x2+3 dx dx (x-1)(x2+1) + Because the integral is exclusively dependent we can use the dh x, Paravartya-Sutra method to expand 2913 A B + y-1 y+ 1 (y-1)(y+1) and then set y=x.