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Assume you have already done the work to prove a precipitate of barium sulphate, BaSO4 forms when 200 mL of 0.4 mol/L solution of barium
Assume you have already done the work to prove a precipitate of barium sulphate, BaSO4 forms when 200 mL of 0.4 mol/L solution of barium chloride, BaCl2, is added to 600 mL of 0.8 mol/L solution of potassium sulphate, K2SO4. What is the mass of the precipitate? O 18.7g O 0.08g 093.4g O 0.48
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