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Given: a. bw = 1 ft; b. fc = 4000 psi and fy = 60 ksi. c. Central floor beam spanning in horizontal direction.
Given: a. bw = 1 ft; b. fc = 4000 psi and fy = 60 ksi. c. Central floor beam spanning in horizontal direction. d. The floor system has a uniform spacing between beams. HINT: For a typical floor system, mid-span sections are subjected to positive bending. Section A-A has a large compression zone: hence compression steel may not be required for additional moment strength in this case. Assuming section will include No. 3 or No. 4 stirrups (compression steel in the section is not shown in the figure which is placed for reinforcement continuity requirements), d-24 in- 3.5 in= 20.5 in and d=24 in-2.5 in = 21.5 in). 7 Slab thickness=5 in. 24 t Figure 1 Continuous Floor System 10 ft 10 ft 3 No. 5 bars b- 72 in No. 7 bars 12 in. Figure 2 T-Beam section at A-A section I-3.5 in. 73 No. 8 bars 2 No. 8 (No. 25) b-72 in. 6 No. 10 (No. 32) 3 No. 7 bars 12 in. Ion. I = 2.5 in. 2.5 in Figure 3 T-Beam Section at B-B section 2 3 No. 5 bars F 24" Figure 4 Rectangular Beam Section at C-C 24 in 5 in. 24 in
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