Assuming p = 1 and g = 9.8 m/s, the equation v' = g - v has solution m v(t) mg k = + Ce-t A man drops from a high flying plane and falls for 5 seconds before opening his parachute. With the parachute closed, = 1 sec-. (a) Find the man's velocity when he opens his parachute (use the initial condition v (0) = 0 to find the value of the constant C). (b) After the chute opens, what must the value of be to get his terminal velocity down to 5 mph? (Use 1 m/sec 2.237 mph.) Assume he has a very long way to fall.