At $105C$ the equilibrium constant for the reaction:

$2HI(g)H_2(g)+I_2(g)$

is $K_P=8\mathrm{.}57e-11.$ If the initial pressure of $HI$ is $0\mathrm{.}00706$atm, what are the equilibrium partial pressures of $HI,H_2,$ and $I_2?$

$p(HI)=$

$p(H_2)=$

$p(I_2)=$