Question
At a bowling alley, two players each score a spare when their bowling balls make head-on, approximately elastic collisions at the same speed with identical
At a bowling alley, two players each score a spare when their bowling balls make head-on, approximately elastic collisions at the same speed with identical pins. After the collisions, the pin hit by ball A moves much more quickly than the pin hit by ball B.
(A response, answer only, without mathematical justification will receive only 15% credit, if correct. Partial credit can potentially be given for an incorrect answer only if there is mathematical evidence for the response.)
Momentum of ball A (mAVbefore) before hitting the pin = momentum of pin (mpinvpinA) after the collision Momentum of ball B (mB Vbefore) before hitting the pin = momentum of pin (mpinvpinB) after the collision
(Note Vbefore is the same for ball A and ball B)
Comparing the Conservation of Momentum information determine which ball has more mass, ball A or ball B?
Step by Step Solution
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Step: 1
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