At a certain temperature, $0\mathrm{.}4811$mol of $N_2$ and $1\mathrm{.}601$mol of $H_2$ are placed in a $3\mathrm{.}00L$ container. $N_2(g)+3H_2(g)2N{H}_3(g)$ At equilibrium, $0\mathrm{.}1601$mol of $N_2$ is present. Calculate the equilibrium constant, $K_c.$