at B. Determine the internal shear force, bending moment, normal force 100kip- 1 y 30 KIP Ax Ay 3' 4' 8' 1/EMC :-17 Ay -100+30(14| + 10(4) + 30sin30(8) Ay : 28. 23 kip SFX = - AX + 36c05 30:0 Ay : 25. 9 B kip NB = 25. 98 kir VB = 28.23-30 -1.77 kip MB"= (28.23) (7)- 30(41: 77.41 kirte NB = - A +25.98 = 25.98kip VR 12 28. 98 -30:-1.71 kip Met= 28.98(7) - 30 (4)100 = 177.61 kip -H INTERNAL SHEAR BENDING MOMENT . NORMAL FORCE Determine the internal shear force, bending moment, normal force @ point b. 25 Kip/FT 25 kip / FJ 12.5 ' Ax 12.5' +EMA = (2 ) . D . 12) Determine the internal shear force + bending moments at points B SonNIm . D um lom 1 3m 1 3m