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At least one of the above answers is NOT correct. (1 pt) The rectangles in the graph below illustrate a left endpoint Riemann sum for

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At least one of the above answers is NOT correct. (1 pt) The rectangles in the graph below illustrate a left endpoint Riemann sum for f (X) = Z + 2X on the interval [2, 6] . The value of this left endpoint Riemann sum is '14526 , and it is an there is ambiguity v i the area of the region enclosed by y 2 f (X) , the x-axis, and the vertical lines x = 2 an X = 6r + 2Xon [2, 6] Le endpoint Riemann sum for y 2 _ The rectangles in the graph below illustrate a right endpoint Riemann sum for f (X) = ' I + 2X on the interval [2, 6] . The value of this right endpoint Riemann sum is 14.626 , and it is an; there is ambiguity V the area of the region enclosed by y I f (X) , the x-axis, and the vertical lines x = 2 andx=6. Right endpoint Riemann sum for y = + 2Xon [2, 6] Using the left and right Riemann sums above, we denitively conclude that 4 5/ -+2XdXS , 2 4 6 I S / i + ZXdX S ( l' 975:1]: 4 4 6 3/ 'i'l'ZXdXSl 2 4 ' Hint: For the last integral, you should consistently choose either to underestimate or overestimate the area. This may require that you use the left Riemann sum for some x-intervals and the right Riemann SI for other x-intervals

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