At the following location a linkage is unable to travel any further, hence the system is equilibrium due to stoppage. Solve for the linkage forces due to the $100$ in$*$lb torque applied at point $3$ as well as the forces at points $1,2,3,4$ and $5.$ All points can be considered to react loads. The corresponding linkage lengths and angles are labeled in the picture. The values are as follows: L$1=7$ in $($distance from point $1$ to point $2),$ L$2=5$ in $($distance from point $2$ to point $3),$ L$3=6\mathrm{.}1$ in $($distance from point $2$ to $5),$ L$4=1$ in $($distance from point $2$ to point $4),$ Theta $1=32$ degrees, Theta$2=$ Theta$3=5$ degrees. Global coordinate system is labeled in the images. You are to only solve for the forces. The linkages are considered perfectly rigid so no material information is needed. Points $1-5$ only react forces. Point $3$ is considered a pinned joint where the applied torque is applied. I have posted this question a couple of times with no actual answers. I am needing help deriving the numerical solution using statics and free body diagrams. If someone could draw the fbd$$s and write out the corresponding equations that would need to be solved in a system solver that would be very helpful. I have a system solver that should be able to solve the system of equations once they are all determined.