At the following location a linkage is unable to travel any further, hence the system is equalibrium due to stoppage. Solve for the linkage forces due to the input torque of $100$ in$*$lbs$.$ The corresponding linkage lengths and angles are labeled in the picture. The values are as follows: L$1=7$ in$,$ L$2=5$ in$,$ L$3=6\mathrm{.}1$ in$,$ L$4=1$ in$,$ Theta $1=32$ degrees, Theta$2=$ Theta$3=5$ degrees. You are to only solve for the forces. The linkages are considered perfectly rigid so no material information is needed. Points $1-5$ only react forces. Point $3$ is considered a pinned joint where the applied torque is applied. I have posted this question a couple of times with not actual answers. I am needing help deriving the numerical solution using statics and free body diagrams. If someone could actually write out the equations and solve the system of equations that would be very helpful