At the following location a linkage is unable to travel any further, hence the system is equilibrium due to stoppage. Solve for the linkage forces due to the $100$ in$*$lb torque as well as the forces at points $1,2,3,$ and $5.$ The corresponding linkage lengths and angles are labeled in the picture. The values are as follows: L$1=7$ in$,$ L$2=5$ in$,$ L$3=6\mathrm{.}1$ in$,$ L$4=1$ in$,$ Theta $1=32$ degrees, Theta$2=$ Theta$3=5$ degrees. You are to only solve for the forces. The linkages are considered perfectly rigid so no material information is needed. Points $1-5$ only react forces. Point $3$ is considered a pinned joint where the applied torque is applied. I have posted this question a couple of times with not actual answers. I am needing help deriving the numerical solution using statics and free body diagrams. If someone could write out the equations and solve the system of equations that would be very helpful$-.$