Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

Avg a Latest mass' (m/s^2) (g) 1 0.244 0.02499 2 0.4713 0.0497 3 0.6941 0.0732 4 0.9079 0.096 5 1.12 0.1177 6 1.364 0.1384

image text in transcribedimage text in transcribed

Avg a Latest mass' (m/s^2) (g) 1 0.244 0.02499 2 0.4713 0.0497 3 0.6941 0.0732 4 0.9079 0.096 5 1.12 0.1177 6 1.364 0.1384 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 222282 Avg a (m/s^2) 0.5 1- Linear Fit for: Latest | Avg a a = mx+b m (Slope): 9.955 +/- 0.2631 m/s^2/g b (Y-Intercept): -0.03423 +/-0.02633 m/s^2 Correlation: 0.9990 RMSE: 0.01847 m/s^2 0.05 0.1 (0.0335, 1.351) (Ax:0.0049 Aa:0.014) mass' (g) PART 2 mg M The force on the glider is F = mg = (M + m)a where M is the mass of the glider and m is the falling mass (plus the hook!). We can determine the acceleration due to gravity by finding the slope of a graph of a vs. m/(M + m).

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image_2

Step: 3

blur-text-image_3

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Introduction to Electrodynamics

Authors: David J. Griffiths

3rd Edition

978-0138053260, 013805326X, 8120316010, 978-8120316010

More Books

Students also viewed these Physics questions