B myopenmath.com Part 1 of 4 To determine the percentage of airline ticket purchasers who actually go to the airport to take their flight, 1122 airline tickets are sampled, and 81.8% of these represented people who actually arrived at the airport for the flight. Construct a 94% confidence interval for the proportion of tickets sold which are actually used for flying. First give the values of n and x. n= 1122 J x: 917 J Next, give the number of successes and failures. The number of successes is computed using 13 (which was given in the problem) and should be rounded to a whole number. successes = 917 J failures = ' \\/' Are the criteria for approximate normality satisfied? 0 Yes, the criteria are met (there are at least 10 successes and failures each). 0 No, the criteria are not met. Part 2 of 4 Convert the given sample percentage to a sample proportion, 33 (a value between 0 and 1). Give 9?, the complement of. No rounding will be necessary. Give the level of confidence as a proportion between 0 and 1. level of confidence = E Give the value of a. Look up 2a /2 in the bottom row of Table A2 as instructed above. This should have 3 places after the decimal. Done 3 myopenmath.com AA To determine an approval rate, 1023 voters are randomly selected, and of these 553 say they approve of the president. Give the 96% confidence interval for the president's approval rate (the population proportion of approvals). First give the values of n and x. n= 1023 \\/ x= 553 J Next, give the number of successes and failures. SUCCESSES = Are the criteria for approximate normality satisfied? 0 Yes, the criteria are met (there are at least 10 successes and failures each). 0 No, the criteria are not met. Part 2 of 4 Give the sample proportion, 15. Round to three significant figures. Give @, the complement off). Use the rounded version of 13, so no rounding will be necessary. =:i Give the level of confidence as a proportion between 0 and 1. level of confidence = [j Give the value of cu. Look up 20/2 in the bottom row of Table A2 as instructed above. This should have 3 places after the decimal. > [B B myopenmath.com Part 1 of 4 Suppose a random sample consists of 421 Americans adults, of these, and that 251 of these are in favor of the death penalty for those who commit murder. Construct a 92% confidence interval for the proportion of Americans who favor the death penalty for those who commit murder. First give the values of n and x. X: ~/| Next, give the number of successes and failures. successes = V failures = '/ Are the criteria for approximate normality satisfied? O No, the criteria are not met. 0 Yes, the criteria are met (there are at least 10 successes and failures each). Part 2 of 4 Give the sample proportion, 13. Round to three significant figures. Give Q, the complement of. Use the rounded version of i), so no rounding will be necessary. =l:] Give the level of confidence as a proportion between 0 and 1. level of confidence = E Give the value of a. Look up za/g in the bottom row of Table A2 as instructed above. This should have 3 places after the decimal. Check Par_ myopenmath.com In a sample of size 356, 259 successes were observed. Compute a 99% confidence interval. First give the values of n and x. n= 356 ~/ x= 259 J Next, give the number of successes and failures. SUCCESSE'S = I failures = I Are the criteria for approximate normality satisfied? No, the criteria are not met. 0 Yes, the criteria are met (there are at least 10 successes and failures each). Part 2 of 4 Give the sample proportion, 13. Round to three significant figures. Give 4, the complement of 13. Use the rounded version of 13, so no rounding will be necessary. Give the level of confidence as a proportion between 0 and 1. level of confidence = C] Give the value of a. Look up za /2 in the bottom row of Table A2 as instructed above. This should have 3 places after the decimal. 2w =:] Check paws