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( B ) - Theory: ( 5 % ) Beginning with the strong form for a 1 D bar A E d 2 u d

(B)- Theory: (5%)
Beginning with the strong form for a 1D bar
AEd2udx2=0
where E is Modulus of Elasticity (from calibration above), A is cross-sectional Area, and u is displacement,
derive the weak form, assuming linear weight function tilde(u)=N1(x)u1+N2(x)u2, and element length L=1.
(Note: Show each step in the derivation fully). The essential and natural boundary conditions are
u|x=0=0
dudx|x=L=S11E
1.03
where S11 is the stress at the final increment in the single linear element (reduced integration) simulation in
(A). Following the weak form derivation, using the Galerkin Method, determine u2 for the boundary
conditions above. Compare the results of this force driven analysis to the displacement driven analysis in
(A). For this questions please use: A = cross sectional area =1m^2; E = youngs modulus =29672.28989MPa; s11=344.015MPa

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