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Based on the caterer's experience, 38% of attendees to events will prefer chicken for the main dish. As the caterer plans for an event attended

Based on the caterer's experience, 38% of attendees to events will prefer chicken for the main dish. As the caterer plans for an event attended by 780 individuals, the normal approximation will be used for the binomial with a correction for continuity. In this case, what is the standard deviation of the number that she would expect to prefer chicken, when determining the probability that at less than 300 will prefer chicken?

Round your answer to 1 decimal place, e.g. 125.7

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