Based on the graph depicting the relationship between two variables, you would conclude the 10 .. Co 6 .. .. . variable 2 4 . . . 2 O a b C variable 1 A. independent variable: discreteominal; relationship best tested with univariate test (e.g. analysis of variance) O B. independent variable: continuous; relationship best tested with bivariate test (e.g. linear regression) O C. dependent variable: discreteominal; relationship best tested with contingency test (e.g. chi-square) O D. dependent variable: continuous; relationship best tested with bivariate test (e.g. linear regression)IA. The study of economics is comprised of three general areas: microeconomics, macroeconomics, and econometrics. What is econometrics? Provide a comprehensive definition of econometrics. IB. What are the two general uses of econometric models? List and briefly discuss both of these. IC. The multiple linear regression model was argued, in general, to be superior to the uni-variate linear regression model for two reasons. Considering your response to IB, discuss the two reasons the multiple regression model is superior.4. A computer program has produced the following ANOVA table for a randomized complete block design, in which each factor appeared once in each block. (30 points) Source Factor Block Error TotalSon:- The given ANOVA table can be completed as; Source d. f. S. S. MSS Treatment 3 498 MST = 166 Block 56 MSB = 28 Error 6 108 MSE = 18 Total 1 1 662 where MST = S. S.T 498 166 ( Mean sum of square due to dift 3 treatment ) MSB = S.S.B 56 28 ( MSS due to block ) d.fb 2 MSE = SSE 108 18 ( Mas due to exion ) d.fe 6 ") Using 2= 0.05, to determine whether there is sufficient evidence to indicate differences among treatment means Hypothesis to be tested Ho: 1/ = 117 = 113= 114 Ha: llitll for at least one itj = 1, 2 ,3 .4 . where li's are corresponding treatment means Theus, test statistic MST MSE Feng = 166 9.2322 18 Now we find F-critical value at = 0.05 with ( 3 ,6 ) degrees of freedom, from F-probability table. "" Fo.os ( 36) = Flap= 8.9410 Since Frat, > Frob there is no strong evidence to indicate differences among treatment means is significant. 1i ) Hypothesis to be tested Ho : Mi = 18 = 18 = els Ha : uit up for at least one it / = 1 12 , 3 where up is the corresponding black mean, i = 1, 2 , 8 Test statistic Fal = MSB 28 1.5.556 NSE 18 and F- critical value at 1= 0.05 with ( 2,6) degrees of freedom . from F - table . Fo.or ( Q, 6 ) = 19.330 Since Fcal <.flab thus there is strong evidence to indicate differences among black means significant cs scanned with camscanner>
