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Based on the result below, explain at length on how it calculated and How do the means compare? Instruction. Use JASP to generate your mean,
Based on the result below, explain at length on how it calculated and How do the means compare?
Instruction. Use JASP to generate your mean, standard deviation, and SEQc) or standard error of the mean for each ofthe 2 groups and use the formula for the 95% condence interval of the mean for small samples (see pages 149-150 for reference), or use this calculator to generate it. An experiment was conducted at the University of CaliforniaBerkeley to study the psychological environment effect on the anatomy of the brain. A group of 19 rats was randomly divided into two groups. Twelve animals in the treatment group lived together in a large cage, furnished with playthings that were changed daily; animals in the control group lived in isolation with no toys. After a month, the experimental animals were killed and dissected. Table E424 gives the cortex weights (the thinking part of the brain) in milligrams. Calculate separately for each treatment the 95% condence interval for the (population) mean of the cortex weight. How do the means compare? DATA: Treatment Control 707 696 740 712 Descriptive Statistics 745 708 Treatment Control 652 749 649 690 Valid 12 676 642 Missing 0 699 698 Mean 676.750 699.286 669 n=7 Std. Error of Mean 10.939 12.041 650 Std. Deviation 37.895 31.858 651 Minimum 627.000 642.000 627 Maximum 745.000 749.000 656 n=12 Sample Mean (M): 676.75 Sample Size (m): 12 Standard Deviation (s): 37.9 Confidence Level: 96%% 8 Result Calculation M = 676.75, 95% CI [652.6695, 700.8305]. M= 676.75 You can be 959% confident that the population mean t= 2.2 (H) falls between 652.6695 and 700.8305. SM= V(37.92/12) = 10.94 Calculate H= M+ 15M H = 676.75 + 2.2*10.94 H = 676.75 + 24.0805 Sample Mean (M): 699.29 Sample Size (n): Standard Deviation (s): 31.86 Confidence Level: 95% Result Calculation M = 699.29, 95% CI [669.8244, 728.7556]. 14 = 699.29 You can be 95% confident that the population mean t = 2.45 (p) falls between 669.8244 and 728.7556. 5M = V(31.86-/7) - 12.04 Calculate H = M+ ISMd H = 699.29 + 2.45*12.04 H = 699.29 + 29.4656 Answer: Treatment Control Mean 676.75 699.29 Standard 37.9 31.86 Deviation Standard Error 10.94 12.04 95% CI 676.75, 95% CI [652.6695, 699.29, 95% CI [669.8244, 700.8305] 728.7556] One Sample T-Test 95% CI for Mean Difference df p Mean Difference Lower Upper Treatment 61.864 11 <.001 control note. for the student t-test location difference estimate is given by sample mean d. alternative hypothesis specifies that different from>Step by Step Solution
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