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Because the mean is very sensitive to extreme values, it is not a resistant measure of center. By deleting some low values and high

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Because the mean is very sensitive to extreme values, it is not a resistant measure of center. By deleting some low values and high values, the trimmed mean is more esistant. To find the 10% trimmed mean for a data set, first arrange the data in order, then delete the bottom 10% of the values and delete the top 10% of the values, th Calculate the mean of the remaining values. Use the axial loads (pounds) of aluminum cans listed below for cans that are 0.0111 in. thick. Identify any outliers, then comp the median, mean, 10% trimmed mean, and 20% trimmed mean. 246 259 268 273 277 279 280 282 285 285 287 288 290 290 294 295 296 300 311 505 A. The outlier(s) is/are 505 pounds. (Type a whole number. Use a comma to separate answers as needed.) B. There are no outliers The median is 286 pounds. (Type an integer or decimal rounded to one decimal place as needed.) The untrimmed mean is 294.5 pounds. (Type an integer or decimal rounded to one decimal place as needed.) The 10% trimmed mean is pounds. (Type an integer or decimal rounded to one decimal place as needed.)

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