\\[ \\begin{array}{l} f\\left(\\frac{\\pi}{6}\ ight)=9 \\\\ f^{\\prime}\\left(\\frac{\\pi}{6}\ ight)=-15 \\\\ g(x)=f(x) \\cos (x), \\text { and } \\\\ h(x)=\\frac{\\sin (x)}{f(x)} . \\end{array} \\] Find \\( g^{\\prime}\\left(\\frac{\\pi}{6}\ ight) \\) and \\( h^{\\prime}\\left(\\frac{\\pi}{6}\ ight) \\) (no rounding, give exact answers). \\[ \\begin{array}{l} g^{\\prime}\\left(\\frac{\\pi}{6}\ ight)= \\\\ h^{\\prime}\\left(\\frac{\\pi}{6}\ ight)= \\end{array} \\]