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begin{tabular}{cccc} hline Sample Size, n & Mean Factor, A2 & Upper Range, D4 & Lower Range, D3 hline 2 & 1.880 & 3.268 &
\begin{tabular}{cccc} \hline Sample Size, n & Mean Factor, A2 & Upper Range, D4 & Lower Range, D3 \\ \hline 2 & 1.880 & 3.268 & 0 \\ 3 & 1.023 & 2.574 & 0 \\ 4 & 0.729 & 2.282 & 0 \\ 5 & 0.577 & 2.115 & 0 \\ 6 & 0.483 & 2.004 & 0 \\ 7 & 0.419 & 1.924 & 0.076 \\ 8 & 0.373 & 1.864 & 0.136 \\ 9 & 0.337 & 1.816 & 0.184 \\ 10 & 0.308 & 1.777 & 0.223 \\ 12 & 0.266 & 1.716 & 0.284 \\ \hline \end{tabular} x=mm (round your response to two decimal places). b) What is the value of ? R=4.48mm (round your responseg to two decimal places). c) What are the UCLx and LCLx using 3-sigma? Upper Control Limit (UCLx)=156.94mm (round your response to two decimal places). Lower Control Limit (LCL)=mm (round your response to two decimal places). d) What are the UCLR and LCLR using 3-sigma? Upper Control Limit (UCLR)=7.96mm (round your rosponse to two decimal places). Lower Control Limit (LCLR)=mm (round your response to two decimal places). , e) If the true diameter mean should be 155mm and you want this as your center (nominal) line, what are the new UCL-; and LCL-? Upper Control Limit (UCL)=mm (round your response to two decimal places). Lower Control Limit (LCLx)=mm (round your response to two decimal places). Refer to Tabio \$6.1 - Foctocs for Computing Control Chart Limits (3 siama) for this probiem. Auto pistons at Wenming Chung's plant in Shanghai are produced in a forging process, and the dameter is a critical factor that must be controlled. From sample sizes of 10 pistons preduced each day, the mean and the range of this diameter have been as follows: a) What is the value of x ? x=mm (round yout rosponse to two decimal places) \begin{tabular}{cccc} \hline Sample Size, n & Mean Factor, A2 & Upper Range, D4 & Lower Range, D3 \\ \hline 2 & 1.880 & 3.268 & 0 \\ 3 & 1.023 & 2.574 & 0 \\ 4 & 0.729 & 2.282 & 0 \\ 5 & 0.577 & 2.115 & 0 \\ 6 & 0.483 & 2.004 & 0 \\ 7 & 0.419 & 1.924 & 0.076 \\ 8 & 0.373 & 1.864 & 0.136 \\ 9 & 0.337 & 1.816 & 0.184 \\ 10 & 0.308 & 1.777 & 0.223 \\ 12 & 0.266 & 1.716 & 0.284 \\ \hline \end{tabular} x=mm (round your response to two decimal places). b) What is the value of ? R=4.48mm (round your responseg to two decimal places). c) What are the UCLx and LCLx using 3-sigma? Upper Control Limit (UCLx)=156.94mm (round your response to two decimal places). Lower Control Limit (LCL)=mm (round your response to two decimal places). d) What are the UCLR and LCLR using 3-sigma? Upper Control Limit (UCLR)=7.96mm (round your rosponse to two decimal places). Lower Control Limit (LCLR)=mm (round your response to two decimal places). , e) If the true diameter mean should be 155mm and you want this as your center (nominal) line, what are the new UCL-; and LCL-? Upper Control Limit (UCL)=mm (round your response to two decimal places). Lower Control Limit (LCLx)=mm (round your response to two decimal places). Refer to Tabio \$6.1 - Foctocs for Computing Control Chart Limits (3 siama) for this probiem. Auto pistons at Wenming Chung's plant in Shanghai are produced in a forging process, and the dameter is a critical factor that must be controlled. From sample sizes of 10 pistons preduced each day, the mean and the range of this diameter have been as follows: a) What is the value of x ? x=mm (round yout rosponse to two decimal places)
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