Below is a calculated output provided for the problem. Please kindly analyze and interpret this output. For k=2: Cluster 1 to Cluster 2 Distance / Cluster 1 Average Distance = 3.829/3.080 = 1.24 Cluster 2 to Cluster 1 Distance / Cluster 2 Average Distance = 3.829/2.746 = 1.39 Average Ratio = 1.32 For k=3: Cluster 1 to Cluster 2 Distance / Cluster 1 Average Distance = 5.005/2.357 = 2.12 Cluster 2 to Cluster 1 Distance / Cluster 2 Average Distance = 5.005/2.438 = 2.05 Cluster 1 to Cluster 3 Distance / Cluster 1 Average Distance = 3.576/2.357 = 1.52 Cluster 3 to Cluster 1 Distance / Cluster 3 Average Distance = 3.576/2.765 = 1.29 Cluster 2 to Cluster 3 Distance / Cluster 2 Average Distance = 3.951/2.438 = 1.62 Cluster 3 to Cluster 2 Distance / Cluster 3 Average Distance = 3.951/2.765 = 1.43 Average Ratio = 1.67 For k=4: Cluster 1 to Cluster 2 Distance / Cluster 1 Average Distance = 2.991/2.738 = 1.09 Cluster 2 to Cluster 1 Distance / Cluster 2 Average Distance = 2.991/2.285 = 1.31 Cluster 1 to Cluster 3 Distance / Cluster 1 Average Distance = 2.576/2.738 = 0.94 Cluster 3 to Cluster 1 Distance / Cluster 3 Average Distance = 2.576/2.559 = 1.01 Cluster 1 to Cluster 4 Distance / Cluster 1 Average Distance = 4.785/2.738 = 1.75 Cluster 4 to Cluster 1 Distance / Cluster 4 Average Distance = 4.785/2.438 = 1.96 Cluster 2 to Cluster 3 Distance / Cluster 2 Average Distance =3.951/2.285 = 1.73 Cluster 3 to Cluster 2 Distance / Cluster 3 Average Distance = 3.951/2.559 = 1.54 Cluster 2 to Cluster 4 Distance / Cluster 2 Average Distance = 5.105/2.285 = 2.23 Cluster 4 to Cluster 2 Distance / Cluster 4 Average Distance = 5.105/2.438 = 2.09 Cluster 3 to Cluster 4 Distance / Cluster 3 Average Distance = 3.808/2.559 = 1.49 Cluster 4 to Cluster 3 Distance / Cluster 4 Average Distance = 3.808/2.438 = 1.56 Average Ratio = 1.56 Which value of k, meaning, number of clusters, is the most appropriate for categorizing wines indicated on the problem? (Enter your response here) Please provide an explanation to justify your answer: (Enter your response here)