Below my python script has been started.

I need to implement this algorithm into code in the section it says "insert code here. "

iii) 1- The Word is displayed with definition

2 - user decides if definition is correct or incorrect

2a) if user is correct about definition then Display Right

3 - otherwise

3a) Display Wrong

4- print correct word and definition

from random import *

def show_flashcard():

"""

This prgroam allows the user to ask for a glossary entry.

In response, the program will randomly pick an entry from

the glossary. Once the deffination of the glossary word is displayed the user

will have to decide if the definition is correct (Y) or incorrect (N).

They are then told if their response is right or wrong.

"""

""" Do not change this first section."""

# Get glossary keys.

keys = list(glossary)

# Choose two distinct keys at random.

sample_keys = sample(keys, 2)

# The first is the entry that will be displayed.

# The definition corresponding to this is the right one.

random_entry = sample_keys[0]

# The second entry will not be displayed.

# The definition corresponding to this is the wrong one.

other_random_entry = sample_keys[1]

# This variable will control whether the user is

# shown the right definition or the wrong one.

right_or_wrong = choice(['right', 'wrong'])

# Pose question.

print('Here is a glossary entry:')

print(random_entry)

print('Here is a possible definition for it:')

if right_or_wrong == 'right':

print(glossary[random_entry])

else:

print(glossary[other_random_entry])

""" End of first section."""

""" Insert your code below.""" <----- NEED HELP WITH THIS PART

""" Do not change anything beyond this point """

# Set up the glossary

glossary = {'word1':'definition1',

'word2':'definition2',

'word3':'definition3'}

# The interactive loop

exit = False

while not exit:

user_input = input('Enter s to show a flashcard and q to quit: ')

if user_input == 'q':

exit = True

elif user_input == 's':

show_flashcard()

else:

print('You need to enter either q or s.')