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Binary Bomb Lab - Phase 2: (x86 assembly) I know that this stage takes an input of 6 numbers (ex. 1 2 3 4 5

Binary Bomb Lab - Phase 2: (x86 assembly)

I know that this stage takes an input of 6 numbers (ex. 1 2 3 4 5 6). The first number is one. I get confused reading the assembly and can't figure out the other steps using the gdb. Could someone translate the assembly and explain the code in simple terms for me, please?

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read_six_numbers function:

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400f73: 400f74: 400f77 400f79: 400f7a push mov push push sub Lea callq pl je callq lea lea mov add p je callq 48 89 e5 41 54 53 48 83 ec 20 48 8d 75 de %rbp %rsp, %rbp %r12 %rbx $6x29 , % rsp -0x39 (%rbp) ,%rsi 40f82 : 40f87 : 400f8b: 400f8d: 400f92: 400f96: 400f9a: 400f9c 400f9e: 400fal: 400fa3: 400fa8: 400fac: 400faf: 400fbl: 400fb5: 400fb6: 400fb8: 400fb9: 4016a4 $8x1,-9x39 (%rbp) 488f92 74 05 e8 dc 06 00 00 48 8d 5d de 4c 8d 63 14 40166e -9x39 (%rbp), %rbx 6x14(%rbx ) ,%r12 (%rbx) ,%eax %eax, %eax %eax,6x4 (%rbx) 400fa8 39 43 04 74 05 40166e add $0x4, srbx 48 83 c3 4 4c 39 e3 75 e9 48 83 c4 2 5b 41 5c 5d C3 %r12 ,%rbx 400f9a $8x29 , % rsp cmp jne add pop pop pop retq %r12 400f73: 400f74: 400f77 400f79: 400f7a push mov push push sub Lea callq pl je callq lea lea mov add p je callq 48 89 e5 41 54 53 48 83 ec 20 48 8d 75 de %rbp %rsp, %rbp %r12 %rbx $6x29 , % rsp -0x39 (%rbp) ,%rsi 40f82 : 40f87 : 400f8b: 400f8d: 400f92: 400f96: 400f9a: 400f9c 400f9e: 400fal: 400fa3: 400fa8: 400fac: 400faf: 400fbl: 400fb5: 400fb6: 400fb8: 400fb9: 4016a4 $8x1,-9x39 (%rbp) 488f92 74 05 e8 dc 06 00 00 48 8d 5d de 4c 8d 63 14 40166e -9x39 (%rbp), %rbx 6x14(%rbx ) ,%r12 (%rbx) ,%eax %eax, %eax %eax,6x4 (%rbx) 400fa8 39 43 04 74 05 40166e add $0x4, srbx 48 83 c3 4 4c 39 e3 75 e9 48 83 c4 2 5b 41 5c 5d C3 %r12 ,%rbx 400f9a $8x29 , % rsp cmp jne add pop pop pop retq %r12

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