birthday is June 3.. therefore the mean is 6 and the standard deviation is .3 To find the z-score

the formula is (data value - mean)/standard deviation. The data value is 6, the mean is 6 and standard deviation is .3

z=(6-6)/.3= 0.

The z-score tell us how many deviations the data value is away from the mean. In my case, my data value is at the mean. This means I am at the mean of the distribution because 0 represents the mean when you transform the data into the standard normal distribution. If my value was greater than 0, I would be some deviations above the mean, and if my value was below zero, I would be some deviations below the mean.

Answer the question below:

Use the invNorm command to find the 35^th percentile using a classmate's mean and standard deviation. Explain the TI Commands and the meaning of your numerical answer.