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block of mass m frictionless 2R g coefficient of kinetic friction u(x) = bx R +x x = d A block of mass m is
block of mass m frictionless 2R g coefficient of kinetic friction u(x) = bx R +x x = d A block of mass m is released from rest at a height 3R above the ground and slides down a frictionless vertical track. When it reaches a height R above the ground it enters a semi-circular frictionless track of radius R. At the bottom of the semi-circular track it enters a horizontal track starting at a = 0. The coefficient of kinetic friction along the horizontal track is non-uniform and varies according to / ( ) = br, where b is a positive constant. The block slides and comes to rest at x = d. The magnitude of the gravitational acceleration is g. (Part a) What is the normal force of the semi-circular track on the block when the block makes an angle 0 as shown in the figure above? Express your answer in terms of m, R, 0, and g as needed. Express you answer using some or all of the following: theta for 0, m, R, g. You may also need to use cos() or sin(). No = Save Submit You have used 0 of 10 attempts Curved Track Motion - Part 2 (of 2) 0.0/1.0 point (graded) (Part b) Calculate the distance d that the block slides along the horizontal track before coming to a rest. Express your answer in terms of m, R, b, and g as needed. Express you answer using some or all of the following: b, m, R, g. Use sqrt() to indicate the square root function if necessary
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