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c++ 3.27 LAB: Leap year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around

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3.27 LAB: Leap year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29 th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year ( 1700,1800 , etc), the year must be evenly divisible by 400 ; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600,1712 , and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712-leapyear Ex: If the input is: 1913 the output is: 1913-notaleapyear \begin{tabular}{l|ll} LAB \\ ACtivirY & 3.27.1: LAB: Leap year & 0/10 \end{tabular} main.cpp Load defaul template

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