C. ANOVA Output The ANOVA results from your output are: F-value: 20.599243 p-value: 6.563427e086.563427e-086.563427e08 (which is less than 0.001) Partial eta squared ( 2 ): 0.231913 47900048 These are the results from ANOVA test. In this we can clearly see that the p-value matches your calculated p-value. And hence the output is correct. D. Sphericity Test Result The null hypothesis represents the assumption of Sphericity. p = .938, which is larger than the alpha of .05, so the null hypothesis has a high probability of being true. We can assume sphericity in the data. Thus, the null hypothesis is not rejected. Verification: Sphericity Test Result: 2=0.12764935104902018 p-value: 0.9381694691864352 (which is greater than 0.05) Reasoning: Since the p-value for Mauchly's test of sphericity is greater than 0.05, we do not reject the null hypothesis that sphericity holds