(c) In which of the preceding two cases, part (a) or part (b), do we have a higher probability of obtaining a sample estimate within $1.00 of the population mean? Why? Recall that the probability from part (a), that the sample mean for 90 males is within $1.00 of the population mean of $37.39, was found to be 0.9606. The probability from part (b), that the sample mean for 90 females is within $1.00 of the population mean of $27.83, was found to be 0.9792. The probability in part (a) is lower v v than the probability in part (b). When calculating the z statistics in parts (a) and (b), the numerators were the same values. The difference came in the denominators for the calculation of the standard error. The standard error for males used in part (a) is calculated using the standard deviation of $4.60 and the sample size 50. Find this value, rounding the result to four decimal places. Vn V90 The standard error for females used in part (b) is calculated using the standard deviation of $4.10 and the sample size 90. Find this value, rounding the result to four decimal places. O - = 90 The standard error for males is higher vy than the standard error for females. This caused the probability for the sample mean to be within $1.00 of the population mean to be higher for females