Question
C++ LANGUAGE /** * Given an input string, count the number of words ending * in 'y' or 'z' -so the 'y' in heavy and
C++ LANGUAGE
/**
* Given an input string, count the number of words ending
* in 'y' or 'z' -so the 'y' in "heavy" and the 'z' in "fez"
* count, but not the 'y' in "yellow". Make sure that your
* comparison is not case sensitive. We'll say that a y
* or z is at the end of a word if there is not an alphabetic
* letter immediately following it.
*
* Do not use any string functions except for substr(),
* at(), and size(). You may use isalpha from cctype as well.
*
*
* Here are some other examples:
* - "fez day" -> 2
* - "day fez" -> 2
* - "day fyyyz" -> 2
*/
int endzy(const string& str)
{
int result;
// Your code goes here
return result;
}
I WILL VOTE THUMB IF ALL PASS
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