C webassign.net/web/Student/Assignment-Responses/tutorial?dep=280 Ignoring the limit temporarily, we have =Xe-13x _ 1 -13x10 = -be-136 e-136 + e-13 + 1 e-13 169 13 169 13 169 The limit lim b - 0 13 -be-13b has the form 0 . co and so requires L'Hospital's Rule. Using this, we have lim e-13b = lim -b b - on 13 b - 0 13e136 -1 L'H lim = b -0 169 13x 169-136 X 0 0 Part 6 of 7 Now we can see that lim -be-136 e-136 + -e-13 e-13 b - co 13 -e-13 4 1 13 169 = 0 - 14 169 160