C6H140 MS Analysis Understanding Check (Spectrum) - The fragment responsible for the peak at m/z59 is attributed to M(+) losing a neutral fragment of MW=a, 59; b, 43 which belongs to the: a, C3H7(.);b,C2H5(+); c, C3H7(+) group. - The presence of a peak at m/z15 implies that the neutral C3H7(.) fragment is a: a, straight; b, branching chain and its structure is: a, G; b, H; c, J - The composition of the fragment at m/z59 is: a, 59/12 =5C s, 43/1.01 =43 H's and 102/16 =6O 's; b, 59 43=16C 's, 1025943 H's and 59 - 43=16 H's; c, 63=3,147=7Hs and 10. - The formula of the fragment at m/z59 is: a, C3H7O(+); b, C3H7O(-); c, C3H7O(.) A B C C6H140 MS Analysis Understanding Check (Spectrum) - The fragment responsible for the peak at m/z59 is attributed to M(+) losing a neutral fragment of MW=a, 59; b, 43 which belongs to the: a, C3H7(.);b,C2H5(+); c, C3H7(+) group. - The presence of a peak at m/z15 implies that the neutral C3H7(.) fragment is a: a, straight; b, branching chain and its structure is: a, G; b, H; c, J - The composition of the fragment at m/z59 is: a, 59/12 =5C s, 43/1.01 =43 H's and 102/16 =6O 's; b, 59 43=16C 's, 1025943 H's and 59 - 43=16 H's; c, 63=3,147=7Hs and 10. - The formula of the fragment at m/z59 is: a, C3H7O(+); b, C3H7O(-); c, C3H7O(.) A B C